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3 years ago

Divide 56 in the ratio 4:7:3

Mathematics

1 answer:

Iteru [2.4K]3 years ago

4 0

Answer:
16,28,12

Explanation:
This is hard for me to explain but hoped it helped :)

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find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6

taurus [48]

Answer:

$f(x) = \frac{6}{x^2} -8$ or $f(x) = -\frac{6}{x^2} + 4$

Step-by-step explanation:

Given

$(x,y) = (1,-2)$ --- Point

$\int\limits^6_2 {(1 + 144x^{-6})} \, dx$

The arc length of a function on interval [a,b]: $\int\limits^b_a {(1 + f'(x^2))} \, dx$

By comparison:

$f'(x)^2 = 144x^{-6}$

$f'(x)^2 = \frac{144}{x^6}$

Take square root of both sides

$f'(x) =\± \sqrt{\frac{144}{x^6}}$

$f'(x) = \±\frac{12}{x^3}$

Split:

$f'(x) = \frac{12}{x^3}$ or $f'(x) = -\frac{12}{x^3}$

To solve fo f(x), we make use of:

$f(x) = \int {f'(x) } \, dx$

For: $f'(x) = \frac{12}{x^3}$

$f(x) = \int {\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = \frac{12}{2x^2} + c$

$f(x) = \frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = \frac{6}{1^2} + c$

$-2 = \frac{6}{1} + c$

$-2 = 6 + c$

Make c the subject

$c = -2-6$

$c = -8$

$f(x) = \frac{6}{x^2} + c$ becomes

$f(x) = \frac{6}{x^2} -8$

For: $f'(x) = -\frac{12}{x^3}$

$f(x) = \int {-\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = -\frac{12}{2x^2} + c$

$f(x) = -\frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = -\frac{6}{1^2} + c$

$-2 = -\frac{6}{1} + c$

$-2 = -6 + c$

Make c the subject

$c = -2+6$

$c = 4$

$f(x) = -\frac{6}{x^2} + c$ becomes

$f(x) = -\frac{6}{x^2} + 4$

3 0

3 years ago

On a coordinate grid, both point (−4, −1) and (2, 6) points are reflected across the y-axis. What are the coordinates of the ref

ella [17]

Answer:

option 4

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

(- 4, - 1 ) → (4, - 1 )

(2, 6 ) → (- 2, 6 )

8 0

3 years ago

A rollercoaster ride reaches a height of 80 feet before it sharply drops. The height above the ground of the rollercoaster car d

Tasya [4]

Answer:

Therefore the car takes 2 s to reach a minimum height from the ground before rising again.

Step-by-step explanation:

Given that a roller coaster ride reach a height of 80 feet.

The height above the ground of the roller coaster is modeled by the function

h(t)=10t²-40t+80

where t is measured in second.

h(t)=10t²-40t+80

Differentiating with respect to t

h'(t)= 10(2t)-40

⇒h'(t)=20t-40

To find the minimum height we set h'(t)=0

∴20t-40=0

⇒20t =40

⇒t=2

The height of the roller coaster minimum when t=2 s.

The minimum height of of the roller coaster is

h(2)= 10(2)²-40.2+80

=40-80+80

=40 feet.

Therefore the car takes 2 s to reach a minimum height from the ground before rising again.

8 0

3 years ago

What is the r value of the following geometric sequence?<br> 2, 6, 18, 54,...

irga5000 [103]

162 is the next in the sequence. It's a sequential value. Just multiply the previous number by 3, and you have you answer.

5 0

3 years ago

Solve by elimination

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

equals 4 you can do rest

7 0

2 years ago