All categories

3 years ago

In triangle ABC, what is the length of side bif B = 48°, C= 81°, and c= 25?

Mathematics

1 answer:

Mashcka [7]3 years ago

7 0

Answer: The correct option is D: Is alloyed with carbon and chromium to make stainless steel.

Explanation: Because of its physical characteristics, iron is a material that tends to oxidize easily. With the chromium alloy stainless steel is created, which for its quality can be used in the manufacture of structural steels.

You might be interested in

Anyone please help me i'm not sure how to do this and please give clear instructions

rewona [7]

-10= 7X - 42
-10 + 42 = 7X
32 = 7X
X = 32/7
X = 4.57

7 0

3 years ago

For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.

vredina [299]

First term (a1) is -1

recursive formula goes like this

$a_n$ is the nth term
$a_{n-1}$ is the term before that

we normally have $a_n=f(a_{n-1})$

we see each term is multipying by -3 to get next one

so that would be
$a_n=-3*a_{n-1}$ where a1=-1

the 3rd option is correct except that it is the explicit formula

so answer is 2nd one

3 0

3 years ago

Identify the outlier of the set:

Finger [1]

Help the math of mine plz

3 0

3 years ago

Use any method to multiply (-14ab)(a + 3b - 4c).

NeX [460]

Answer:

-14a^2b-42ab^2+56abc

Step-by-step explanation:

You can use the FOIL method

multiply the first numbers

then inner

then outer

then last

8 0

4 years ago

Calculus 2: I need help with u substitution and intergration by parts. Can someone help me understand the concept?

snow_lady [41]

Computing an integral by substitution is the reverse of the chain rule for computing the derivative. Substitution is intended to rewrite a complicated-looking integral involving the derivative of some component expression as another much simpler integral. For example, if $u=f(x)$ , then $\mathrm du=f'(x)\,\mathrm dx$ and

$\displaystyle\int f(x)f'(x)\,\mathrm dx=\int u\,\mathrm du$

###

Integration by parts is the reverse of the product rule for derivatives:

$(f(x)g(x))'=f'(x)g(x)+f(x)g'(x)\implies f(x)g'(x)=(f(x)g(x))'-f'(x)g(x)$

Integrating both sides with respect to $x$ gives

$\displaystyle\int f(x)g'(x)\,\mathrm dx=\int(f(x)g(x))'\,\mathrm dx-\int f'(x)g(x)\,\mathrm dx$

$\displaystyle\int f(x)g'(x)\,\mathrm dx=f(x)g(x)-\int f'(x)g(x)\,\mathrm dx$

###

Personally, I think the best way to grasp the idea behind the two methods is to practice. You start to notice patterns to the point where knowing which is the "right" method to use becomes second nature.

4 0

3 years ago