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3 years ago

10

A bookshop has a sale.

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

The price been reduced by a percentage of 40%

Step-by-step explanation:

we know that

$39.95 -----> represent the 100%

so

The difference of prices is equal to ($39.95-$23.97)=$15.98

Using proportion

Find the percentage of the difference

100/39.95=x/15.98

x=100*15.98/39.95

x=40%

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Find the area of the regular hexagon if a side is 30m.

vovangra [49]

The answer is A.
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4 0

3 years ago

Read 2 more answers

A certain store sells only T-shirts. Let the random variable X represent the number of T-shirts bought from the store on any day

faltersainse [42]

Answer:

$(a)\ \mu_y = 1125$

$(b)\ \sigma_y = 300$

Step-by-step explanation:

Given

$\mu_x = 75$ -- Mean of T-shirts

$\sigma_x = 20$ -- Standard deviation of T-shirts

$Rate = \$ 15$

Solving (a): The mean of the revenue $(\mu_y)$

To solve this, we use:

$\mu_y = Rate * \mu_x\\$

This gives:

$\mu_y = 15 * 75$

$\mu_y = 1125$

Solving (b): The standard deviation of the revenue $(\sigma_y)$

To solve this, we use:

$\sigma_y = \sqrt{Rate^2 * \sigma_2^2}$

This gives:

$\sigma_y = \sqrt{15^2 * 20^2}$

$\sigma_y = \sqrt{90000}$

$\sigma_y = 300$

7 0

3 years ago

What is the value of 4b ÷ 3, if b =3

Mice21 [21]

The value is 4 because 4b is also 4 times three which is twelve then you divide 12 by three and get 4

7 0

3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

4 0

3 years ago

What is the slope for the following question? <br> Y = 3x - 2

quester [9]

it should be x=2/3.

6 0

3 years ago