there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
Evalute b^2+ 4, if b = -3 13 10 - 5 -2
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there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".