What could be partial quotients for 145divided by 5

Josh wants to determine the number of loaves of bread he can bake using the 13 and one-third cups of flour he has. If each loaf

motikmotik

Answer:

Approximately 4 loaves of bread.

Step-by-step explanation:

Let us get out the total amount of flour that Josh has first of all. This is $13\frac{1}{3}$ cups of flour.

Each lof requires $3\frac{4}{5}$ cups of flour. This means that to make a loaf, he will be taking out this quantity of flour from the whole lot.

To get the total number of loaves he can make with this quantity of flour, we will have to divide the total quantity of flour available by the quantity required to make a single loaf.

This will be $13\frac{1}{3}$ ÷ $3\frac{4}{5}$ = $3\frac{29}{57}$ . This is approximately 4 loaves of bread

3 0

3 years ago

Read 2 more answers

Use two points to enter an equation for the function. Give your answer in the form a(b)^n. In the event that a = 1, give your an

levacccp [35]

Answer:

$m(n) = 24 (0.75)^n$

Step-by-step explanation:

1) The two points are:

a) On the first swing she swings forward by 18 degrees: (1, 18)

b) On the second swing she only comes 13.5 degrees forward: (2,13.5)

2) The general equation using the form given is:

$m(n)=A(B)^n$

3) Substitute the two points:

$18=A(B)\\ \\ 13.5=A(B)^2$

4) Divide the second equation by the first one:

⇒ 13.5 / 18 = B

⇒ B = 0.75

5) Substitue B = 0.75 into the first equation:

18 = A (0.75) ⇒ A = 18 / 0.75 = 24

Hence, the equation is:

$m(n) = 24 (0.75)^n$

5 0

4 years ago

Scientists have found a relationship between the temperature and the height above a distant planet's surface. , given below, is

ikadub [295]

The question is incomplete, the complete question is below:

Scientists have found a relationship between the temperature and the height above a distant planet's surface. , given below, is the temperature in Celsius at a height of kilometers above the planet's surface. The relationship is as follows: T(h) = 30.5 -2.5h.

a) Calculate T^-1(x)

b) T^-1(15)

Answer:

a) $T^{-1} (x)= \frac{30.5-x}{2.5}$