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3 years ago

5y2 + y + 2y2 – 7y - 5y2 + 4x How to simplify

Mathematics

1 answer:

Damm [24]3 years ago

3 0

Combine like terms to get 2y2-2y+4x

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Which of these steps in constructing an inscribed square using technology

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<span>Mark the point of intersection between Circle eight in line A.B.</span>

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3 years ago

PLEASE HELP I dont know WHAT IM DOING! THANK YOU!

jeka57 [31]

I think the answer would be

X=1.5
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3 years ago

Read 2 more answers

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

What is an equivalent expression for x=3y-2

ioda

X = 3(y - 2/3) ...distribute thru the parenthesis
x = 3y - 6/3...reduce
x = 3y - 2

so ur answer is : x = 3(y - 2/3)

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3 years ago

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icang [17]

Answer:

Step-by-step explanation:

Quadratic equations of the form (x - h)^2 + k = 0 can be solved using square roots: Take the square root of both sides, prefacing the right side with " ± "

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3 years ago