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Serga [27]
3 years ago
9

Suzie bought an antique jewelry box for $34.50. It originally cost $8.75 when it was made. Its value has increased $0.75 a year

since it was made and it is now 83 years old. If Suzie were to sell it for what it is worth, how much money would she make? (Please show steps)
Mathematics
2 answers:
timama [110]3 years ago
7 0

Answer:

if she would sell it for what it is worth now she would make $36.50

Step-by-step explanation:

0.75 x 83 = 62.5

62.5 + 8.75 = 71

71 is how much it is worth now

71 - 34.5 = 36.5

36.50 is how much she would make

bogdanovich [222]3 years ago
3 0

Answer:

$36,50

Step-by-step explanation:

That is correct to me. You do those exact steps to arrive at that answer.

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If 2a-b:2a+b=1:2find the value of a:b​
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Answer & Step-by-step explanation:

2a - b : 2a + b = 1 : 2

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-                         Elimination

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3 0
3 years ago
A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r
svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, h^2 + b^2 = 16^2 = 256 \dotsc\;(1) because it is a right angle triangle.

It is given that \frac{db}{dt} = 1

Now differentiate (1) with respect to t (time) :

\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}

\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that 16 \sin{\theta} = b. When b = 8, then \theta = \arcsin{0.5} = \ang{30}.

Differentiate the above equation w.r.t t

\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}

c. The area of the triangle is given by A = 0.5\times h \times b. Differentiating w.r.t t,

\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}

Plugging in b = 8, h = 13.856, \frac{dh}{dt} = -0.588,

\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}

8 0
4 years ago
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