This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left
First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one
70 this is your answer i hope
Answer:
420
Step-by-step explanation:
you would first work out 3/4 of 560 so you would do 560÷4 which gives you 140. then you will times 3 by 140 which gives you 420. 420 went to the trip
