What do you need help on which problem
Answer:
46.761g/mol
Explanation:
Given parameters:
Element = Hilarium , Hi
Isotopes: Hi- 45, Hi-46 and Hi- 48
Natural abundance of Hi-45 = 18.3%
Hi-46 = 34.5%
Hi-48 = 47.2%
Unknown:
Atomic weight of naturally occurring Hilarium = ?
Solution:
Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.
We can use the expression below to find this value:
Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈
m is the atomic mass of each isotope and α is the abundance
Atomic weight = (45 x
) + (46 x
) + (48 x
)
Atomic weight of Hi = 8.235 + 15.870 + 22.656 = 46.761g/mol
When
1-Bromopropane is treated with
methoxide it undergoes
SN² Reaction. The product formed is
Methyl Propyl Ether. This type of reaction is very important in synthesizing
Asymmetric ethers. The alkoxides are oftenly generated by reacting Alcohols with sodium metal, which on elimination of Hydrogen gas produces corresponding alkoxide. The reaction of given statement is as follow,
Answer:
If it is unsaturated, we can dissolve some more amounts of potassium nitrate into it Explanation:
An igneous rock is crushed into little shards of rock called sediment, the sediment is then packed together by other rocks or strong forces, that form together to make a Sedimentary rock.