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2 years ago

Choose the statement that best completes the sentence.

Chemistry

2 answers:

Darina [25.2K]2 years ago

4 0

The collisions of the molecules

Kipish [7]2 years ago

4 0

Answer: Option (b) is the correct answer.

Explanation:

In solids, the force of attraction are strong therefore, there will be no collision between the particles.

In liquids, there will be less force of attraction between the molecules therefore, there will be collisions between the molecules.

In gases, as there is no force of attraction between the molecules therefore, there will be more collisions.

Thus, we can conclude that whether a substance is a gas, liquid, or solid is dependent on the natural attractive forces between molecules and the collisions between the molecules.

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Find the volume of a cereal box that has the dimensions of 35.2 cm x 220 cm x 6.0 cm

notsponge [240]

Answer:

Volume = 35.2×220×6.0 = 46464 centimeters³

Explanation:

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2 years ago

During which phase of mitosis does the cell begin to split into two daughter cells

artcher [175]

Answer:

$\text{Telophase}$

Explanation:

Telophase is the process that separates the duplicated genetic material carried in the nucleus of a parent cell into two identical daughter cells.

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2 years ago

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The pressure of a sample of helium is 1.556 atm in a 268.5 mL container. If the container is compressed to 112.4 mL without chan

Rainbow [258]

Answer:

a. 3.72 [atm]

Explanation:

For a gas at constant temperature, (with no change in number of molecules of the gas), we can apply Boyle's Law: $P_1V_1=P_2V_2$

$(1.556[atm])(268.5[mL])=P_2(112.4[mL])$

$\dfrac{(1.556[atm])(268.5[mL\!\!\!\!\!\!\!\!{--}])}{112.4[mL \!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})}{112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}$

$3.716957[atm]=P_2$

It seems like the answer should have 4 significant figures since all of the other quantities have 4 significant figures, but the closest answer choice of those provided is a. 3.72

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2 years ago

An object can become electrically charged if it gains or loses which particles?

Sunny_sXe [5.5K]

Answer:

if it gains or loses neutrons

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3 years ago

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A reaction has a rate constant of 1.15 x 10^−2 /s at 400K and 0.685 /s at 450K.

n200080 [17]

Answer:

a) the activation barrier = 122.3 kJ/mol

b) The rate constant at 425 K = 0.1001 /s

Explanation:

Step 1: Data given

Rate constant k1 = 1.15 * 10^−2 /s at 400K (= T1)

Rate constant k2 = 0.685 /s at 450K (=T2)

Step 2: Determine the activation barrier for the reaction.

To determine the activation energy we will use the two-point Arrhenius equation:

ln(k₂/k₁) = (Ea/R)((1/T1) - (1/T2))

⇒ with Ea = the activating energy

⇒ with R = the gas constant = 8.314 J/mol* K

⇒ with k1 = rate constant 1 = 1.15 *10^-2 /s

⇒ with T1 = Temperature 1 = 400 K

⇒ with k2 = rate constant 2 = 0.685/s

⇒ with T2 = temperature 2 = 450 K

= - (Ea/R)(T₁ - T₂)/T₁T₂

Ea = (R*ln (k2/k1)) / ((1/T1)- (1/T2))

Ea = (8.314* ln(0.685/0.0115)) / ((1/400) - (1/450))

Ea = 122327.6 = 122.3 kJ/mol

B) What is the value of the rate constant at 425 K

For rate constant at 425 K.

Substitute the value of activation energy as 122327.6 J/mol, initial temperature as 400 K, final temperature as 425 K, rate constant at 400 K

1/T1 - 1/ T3 = 1/400 - 1 /425 = 1.47*10^-4

⇒ with T1 = the initial temperature = 400 K

⇒ with k1 = the rate constant at 400 K = 1.15 * 10^-2 /s

⇒ with T3 = the nex temperature = 425 K

⇒ with k3 = the rate constant at 425 K

ln(k3/k1) = Ea/R * ((1/T1)- (1/ T3))

⇒ with k3 = the rate constant at 425 K

⇒ with T3 = 425 K

k3/k1 = e^(Ea/R * ((1/T1)- (1/ T3)))

k3 = k1* e^(Ea/R * ((1/T1)- (1/ T3)))

k3 = 0.0115 * e^(122327.6/8.314 * (1.4710^-4))

k3 = 0.0115* e^2.1643

k3 = 0.1001 /s

4 0

3 years ago