Determine the number of triangles ABC possible with the given parts. b = 24, c = 29, B = 43°

Mathematics

1 answer:

goldenfox [79]2 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

In general, if the given angle is opposite the shorter of the two given sides, there will be 0 or 2 possible triangles. The attachments show the two possibilities.

There will be zero possible triangles if the ratio of sides is less than the sine of the angle. Here, 24/29 ≈ 0.8276, sin(43°) ≈ 0.6820. The ratio of sides is greater, so there are two possible triangles.

If the given angle is opposite the longer of the two given sides, there is one possible triangle. The same is true if the given angle is between the two given sides.

You might be interested in

In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53 × 10−1

tresset_1 [31]

For the answer to the question above,
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".

b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration

c) Now use a = v² / r
where a was found above
and r was given

d) period T = 2π / ω = 2πr / v
where v was found above
and r was given

7 0

3 years ago

What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?

ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$