All categories

3 years ago

Early detection of cancer __________.

2 answers:

6 0

<span>Early detection of cancer increases the likelihood of living, increases the chance for a cure and makes it less likely that the cancer has metasasized. the time spent in hospital depends more on the the type of cancer and what treatment is appropriate. Early detection means finding the cancer whil it is still relatively simple, before large tumours and secondary tumours have developed.</span>

Olenka [21]3 years ago

5 0

It's B. increases the chance for a cure. Just took the test and got it right. Hope this helps!

You might be interested in

kiyoko lives 7/8 of a mile from school. if she walks half the distance and runs the other half, both to and from school, how man

love history [14]

If she runs half the distance to school, and runs the same back, this means that she suns 7/8 miles in a day. In 5 days, 5 x 7/8 = 35/8 miles (or 4.375 miles in 5 days).

8 0

3 years ago

Someone help please and please make sure it’s right :)

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

5x + 5 = 4x + 16 ( being alternate angles)

5x - 4x = 16 - 5

x = 11

Hope it will help :)

6 0

2 years ago

4x+6<-6<br> Solve for x put steps

chubhunter [2.5K]

First move the constant to the other side causing it to change sides

4x<-6-6

Then calculate the difference (-6-6)

4x<-12

Now divide both sides by 4

X<-3

Then you are left with your answer:

x<-3

Hope this helps! :3

4 0

3 years ago

Read 2 more answers

Which step is wrong, Step 1, Step 2, Step 3 or Li didn't make a mistake

mart [117]

Hello there!

The correct answer is option A

Instead of the division sign, it suppose to be multiply.

Have fun on Khan Academy!

7 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):