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3 years ago

Early detection of cancer __________.

2 answers:

6 0

<span>Early detection of cancer increases the likelihood of living, increases the chance for a cure and makes it less likely that the cancer has metasasized. the time spent in hospital depends more on the the type of cancer and what treatment is appropriate. Early detection means finding the cancer whil it is still relatively simple, before large tumours and secondary tumours have developed.</span>

Olenka [21]3 years ago

5 0

It's B. increases the chance for a cure. Just took the test and got it right. Hope this helps!

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mrs harris pickled vegetables from her garden to take to the market. She picked 30 tomatoes. If 40% of all of the vegetables she

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Mrs.Harris picked 70 vegetables

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3 years ago

Simplify by combining like terms: -18+3(5x-2)+8=46

Dmitriy789 [7]

-18 +3(5x-2)+8=46

-18 + 15x-6 +8 = 46

-18 + 15x +2 =46

-16 +15x =46

15x = 62

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Plastic cups come in packages of twenty-four, and straws come in packages of twenty. If you want to end up with the same total n

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120 of each. 5 packs of cups and 6 packs of straws

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3 years ago

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Which expressions simplify to 0? Check all that apply. 8g – 8g, (–2g) – 2g, 5g + (–5g), One-half g + one-half, g Negative two-th

victus00 [196]

We have been given 4 expressions. We are asked to choose the expressions, which simplifies to 0.

Let us check our given choices one by one.

1. $8g-8g$

$8(g-g)$

$8(0)=0$

When we will subtract 8g from 8g, we will get 0. Therefore, expression $8g-8g$ simplifies to 0.

2. $(-2g)-2g$

Let us remove parenthesis.

$-2g-2g$

Upon combining like terms, we will get:

$-4g$

Since $(-2g)-2g$ simplifies to $-4g$ , therefore, expression $-2g-2g$ is not a correct choice.

3. $5g+(-5g)$

Let us remove parenthesis.

$5g-5g$

Upon combining terms, we will get:

$5g-5g=0$

Since $5g+(-5g)$ simplifies to 0, therefore, expression $5g+(-5g)$ is a correct choice.

4. $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$

Let us combine the terms as:

$\frac{1+1}{2}g-\frac{2}{3}g+\frac{2}{3}g$

$\frac{2}{2}g-\frac{2}{3}g+\frac{2}{3}g$

$g-g(-\frac{2}{3}+\frac{2}{3})$

$g-g(0)$

$g-(0)=g$

Since $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$ simplifies to $g$ , therefore, expression $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$ is not a correct choice.

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4 years ago

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