⇒If parallelogram A B CD is a rectangle, then Diagonals of parallelogram that is of rectangle will be of equal Length.
That is , Diagonal AC = Diagonal B D
⇒Given, AX= 3 y- 5
So, AC= 2 × (3 y- 5)→→[Diagonals of Parallelogram Bisect each other]
And, B D = 5 y
So,A C = B D ⇒→→Diagonals of a rectangle are equal.]
→2 ×(3 y - 5) = 5 y
→ 6 y - 10 = 5 y →→[Using Distributive Property of subtraction with respect to multiplication]
Combining Like terms that is Variables with Variables and Constant with Constant.
→ 6 y - 5 y = 10
→ y = 10
Answer:
$677.18
Step-by-step explanation:
Data provided in the question:
Bill’s nominal income in 1990 = $1,009 per month
CPI value in the year 1990 = 149
CPI value in the year 2017 = 192
Now,
The Consumer price index ( CPI ) is given as :
CPI = 
thus,
for the given case of year 1990
149 = 
or
Real income in 1990 = 
or
Real income in 1990 = $677.18
Answer:
one solution
Step-by-step explanation:
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
6
Step-by-step explanation:
