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vova2212 [387]
3 years ago
13

Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in

the string. Ex: If the input is: n Monday, the output is:
Computers and Technology
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

import java.util.Scanner;

public class ANot {

   public static void main(String[] args) {

       System.out.println("Enter a character");

       Scanner in = new Scanner(System.in);

       char character = in.next().charAt(0);

       System.out.println("Enter a string");

       String string = in.next();

//Calling the method        

System.out.println(countChar(character,string));

   }

   public static int countChar(char a, String in){

       int counter =0; // initialize counter

       for (int i=0;i<in.length();i++){

           if(a == in.charAt(i))

               counter++;

       }

       return counter;

   }

}

Explanation:

This program is written in Java Programming language.

We created a method countChar that returns a integer called counter

Using a for loop in the method we iterate through the string object and check (a == in.charAt(i)) so as to increase counter when ever there is a match.

In the main method a Scanner Class is used to request user to input a character and a string which is passed to countChar when called.

NOTE that this program has considered lower case letters to be different from upper cases as such a is not equal to A

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HELP ASAP, AND YES I KNOW, WRONG CATEGORY. SORRY!
Anastasy [175]

Answer:

A. ensemble.

Explanation:

A musical ensemble can be defined as a group of people who play instrumental and vocal music. It is also known as a music group and carries a distinct name. The word ensemble is derived from the Middle French ensemblée, meaning together at the same time.

A rock band will come under the category of a musical ensemble as it is also a group of people performing instrumental music or vocal music.

Therefore, option A is correct.

3 0
3 years ago
Which one of these is the most commonly used hardware interface for attaching peripherals to a microcomputer?
Tanzania [10]
Hey there!

The most commonly used hardware interface for attaching peripherals to a microcomputer is the universal series bus, or USB, port. Many computers have at least 2 to 4 USB ports that allow for multiple devices to be plugged in at once. In terms of wired devices as opposed to wireless, this is the main way that a mouse, a keyboard, a smartphone (for charging and syncing information), and many other devices are connected to computers. 

Hope this helped you out! :-)
4 0
3 years ago
A termination condition in a loop is analogous to________in a recursive method.
Varvara68 [4.7K]

Answer:

b) iteration.

Explanation:

There are various algorithms which are used in computer programming. Iteration is also a type of algorithm which is used to create loops. The instructions are inserted once and then these instructions are repeated to create a loop function.

8 0
3 years ago
Challenge #3: Create a network that keeps everyone connected even if one of the lines is cut Insert as many lines as needed
zvonat [6]

Answer:

To create a redundant computer network, The star network topology is adopted.

Explanation:

Note that topology is not a type of network but a top view of how the network looks like or is connected.

To make a network redundant, interconnect every computer to one another in the network, so even when a line or an ethernet cable ( the connector) makes, there is no loss of connection.

This form of network is not recommended for large computer networks as it would result in confusion due to excess connection cables running in the network.

7 0
3 years ago
Exercise1 : Defining Circle type and Creating a Driver Circle class private members double radius double xPos double yPos public
asambeis [7]

Answer:

Aee explaination

Explanation:

1) class_circle.h

#include<iostream>

#include<cmath>

#include<iomanip>

#define PI 3.14159

using namespace std;

class circle

{

private:

double radius,xPos,yPos;

public:

double diameter();

double area();

double circumference();

double getRadius();

double getX();

double getY();

void setX(double x);

void setY(double y);

double distanceToOrigin();

bool intersect(const circle& otherCircle);

bool setRadius(double r);

};

class CircleDriver:public circle

{

private:

circle circ1;

circle circ2;

void obtainCircles();

void printCircleInfo();

public:

void run();

};

2) class_circle.cpp

#include "class_circle.h"

double circle::diameter()

{

return (radius * 2);

}

double circle::area()

{

return PI * radius * radius;

}

double circle::circumference()

{

return 2 * PI * radius;

}

double circle::distanceToOrigin()

{

return sqrt((xPos * xPos) + (yPos * yPos));

}

double circle::getRadius()

{

return radius;

}

double circle::getX()

{

return xPos;

}

double circle::getY()

{

return yPos;

}

void circle::setX(double x)

{

xPos = x;

}

void circle::setY(double y)

{

yPos = y;

}

bool circle::setRadius(double r)

{

if(r > 0)

{

radius = r;

return true;

}

else

{

radius = 0;

return false;

}

}

bool circle::intersect(const circle& otherCircle)

{

double dist1 = (radius - otherCircle.radius) * (radius - otherCircle.radius);

double dist2 = ((xPos - otherCircle.xPos) * (xPos - otherCircle.xPos)) + ((yPos - otherCircle.yPos)*(yPos - otherCircle.yPos));

double dist3 = (radius + otherCircle.radius) * (radius + otherCircle.radius);

if((dist1 <= dist2 ) && (dist2 <= dist3) && (dist1 < dist3))

return true;

else

return false;

}

void CircleDriver::obtainCircles()

{

double x,y,rad;

cout<<"Enter xPos yPos circle 1 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 1 :";

cin>>rad;

}while(rad <= 0);

circ1.setX(x);

circ1.setY(y);

circ1.setRadius(rad);

cout<<"\n\nEnter xPos yPos circle 2 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 2 :";

cin>>rad;

}while(rad <= 0);

circ2.setX(x);

circ2.setY(y);

circ2.setRadius(rad);

}

void CircleDriver::printCircleInfo()

{

cout<<setprecision(6)<<endl;

cout<<"\n\nInformation for Circle 1:"<<endl;

cout<<"location:( "<<circ1.getX()<<" ,"<<circ1.getY()<<" )"<<endl;

cout<<"diameter: "<<circ1.diameter()<<endl;

cout<<"area: "<<circ1.area()<<endl;

cout<<"circumference: "<<circ1.circumference()<<endl;

cout<<"distance from the origin: "<<circ1.distanceToOrigin()<<endl;

cout<<"\n\nInformation for Circle 2:"<<endl;

cout<<"location:( "<<circ2.getX()<<" ,"<<circ2.getY()<<" )"<<endl;

cout<<"diameter: "<<circ2.diameter()<<endl;

cout<<"area: "<<circ2.area()<<endl;

cout<<"circumference: "<<circ2.circumference()<<endl;

cout<<"distance from the origin: "<<circ2.distanceToOrigin()<<endl<<endl;

if(circ1.intersect(circ2))

cout<<"The circles intersect."<<endl;

else

cout<<"The circles does not intersect."<<endl;

}

void CircleDriver::run()

{

obtainCircles();

printCircleInfo();

}

3) main.cpp

#include "class_circle.h"

int main()

{

CircleDriver myDriver;

myDriver.run();

return(0);

}

Please refer below output for reference

Enter xPos yPos circle 1 :0.0 50.0

Enter radius for circle 1 :100.0

Enter xPos yPos circle 2 :50.0 0.0

Enter radius for circle 2 :100.0

Information for Circle 1:

location:( 0 ,50 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

Information for Circle 2:

location:( 50 ,0 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

The circles intersect.

Process returned 0 (0x0) execution time : 18.245 s

Press any key to continue.

8 0
4 years ago
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