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Pie
3 years ago
15

-8= 3-5(x+6) solving algebraicaily​

Mathematics
2 answers:
Helga [31]3 years ago
8 0

Answer:

x = -19/5

Step-by-step explanation:

-8 = 3-5(x+6)

Distribute.

-8 = 3-5x-30

Combine like terms.

-8 = -27-5x

Add 27 on both sides.

-8 = -27-5x

<u>+27   +27</u>

19 = -5x

Divide by -5 on both sides.

19 = -5x

<u>/-5   /-5</u>

-19/5 = x

Hope this helps you a little bit! Sorry if it get confusing...have an amazing day c:

SOVA2 [1]3 years ago
4 0

Let's solve your equation step by step

-8=3-5(x+6)

Step 1: simplify both sides of the equation

-8=3-5(x+6)

-8=3+(-5)(x)+(-5(6) (distribute)

-8=3+-5x+-30

-8=(-5x)+(3+-30) (combine like terms)

-8=-5x+-27

-8=-5x-27

Step 2: flip the equation

-5x-27=-8

Step 3: add 27 to both sides

-5x-27+27=-8+27

-5x=19

Step 4: Divide both sides by -5

-5x/-5 = 19/-5

Answer : x= -19/5

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The average homicide rate for the cities and towns in a state is 10 per 100,000 population with a standard deviation of 2. If th
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Answer:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-10}{2})=P(Z>-1)  

And we can find this probability with the complement rule:  

P(Z>-1)=1-P(Z  

Step-by-step explanation:

Previous concepts  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem  

Let X the random variable that represent the average homicide rate for the cities of a population, and for this case we know the distribution for X is given by:  

X \sim N(10,2)  

Where \mu=10 and \sigma=2  

We are interested on this probability  

P(X>8)  

And the best way to solve this problem is using the normal standard distribution and the z score given by:  

z=\frac{x-\mu}{\sigma}  

If we apply this formula to our probability we got this:  

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-10}{2})=P(Z>-1)  

And we can find this probability with the complement rule:  

P(Z>-1)=1-P(Z  

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