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3241004551 [841]

3 years ago

8

To get to your school, 25 of the students walk, 13 of the students ride the bus, and the rest come in cars. How many students co

me to school in cars?

1 answer:

Otrada [13]3 years ago

6 0

Answer:

12

Step-by-step explanation:

subtract 25 minus 13 and you get 12 which means 12 students come in cars

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Can someone please help me

Rus_ich [418]

Answer:

The answer is (1/2 x 18 + 5)

Step-by-step explanation:

This is the answer because that is the only thing in the options higher than Keisha's expression.

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

4 0

3 years ago

Can a decimal be an integer or a whole number ?

WINSTONCH [101]

It can only become a whole number when its over .99 such as 1.00 is a whole number and 7.24 is also a hole get it

5 0

4 years ago

Read 2 more answers

Write the repeating decimal as a fraction.<br> 0.928

solmaris [256]

To convert the decimal 0.928 to a fraction, just follow these steps:

Step 1: Write down the number as a fraction of one:

0.928 = 0.928

1

Step 2: Multiply both top and bottom by 10 for every number after the decimal point:

As we have 3 numbers after the decimal point, we multiply both numerator and denominator by 1000. So,

0.928

1

= (0.928 × 1000)

(1 × 1000)

= 928

1000

.

Step 3: Simplify (or reduce) the above fraction by dividing both numerator and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD(928,1000) = 8. So,

(928÷8)

(1000÷8)

= 116

125

when reduced to the simplest form.

7 0

3 years ago

Read 2 more answers

Dominic is traveling through state of orgen. He drove 66.4 miles. The total distance of his trip is 233.25 what is the distance

nikklg [1K]

He still has 166.85 miles to go

4 0

4 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago