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3241004551 [841]
3 years ago
8

To get to your school, 25 of the students walk, 13 of the students ride the bus, and the rest come in cars. How many students co

me to school in cars?
Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

12

Step-by-step explanation:

subtract 25 minus 13 and you get 12 which means 12 students come in cars

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P(n) = n + 1; Find p(6)
True [87]

Answer:

p(6) = 7

Step-by-step explanation:

p(n) = n + 1

Let n = 6

p(6) = 6 + 1

p(6) = 7

7 0
3 years ago
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Molly wrote a computer program that generates two random numbers between one and 10. When she runs it, what is the probability t
Igoryamba

Answer:

Step-by-step explanation:

The accepted values are  2 3 4 5 6   One is not counted. It says between.            

The total number of ways each dice can be thrown is  2 3 4 5 6 7 8 9 Ten is not counted. Same reason.

5/8 * 5/8 = 25/64 = 0.39

3 0
2 years ago
Solve the equation: <br><br> 9 (x − 9)−3 = −4 (2x + 4)<br><br> 4<br><br> -4<br><br> 100<br><br> 68
Nina [5.8K]

Answer:


Step-by-step explanation:

Applying BODMAS here;

We first solve what is in the brackets:

9x - 81 -3 = -8x - 16

We then put the like terms together:

9x + 8x = -16 + 81 + 3

We then do the addition:

17x = -16 + 84

We then do the subtraction:

17x = 68

Simplifying this gives:

x = \frac{68}{17} = 4

8 0
3 years ago
The owner of an apple orchard ships apples in boxes that weigh 2 kilograms ( kg ) when empty. the average apple weighs 0.25 kg a
Lunna [17]

Answer: C=40

Step-by-step explanation: X=40 APPLES PER BOX.  

PROOF:

2+.25*40=12

2+10=12

12=12

6 0
3 years ago
NEED ANSWER ASAP REALLY IMPORTANT i will take any of the answers
dedylja [7]

1. \: MC  \: is \:  tangent \:  to \:  (B)\Rightarrow \widehat{BCM}=90° \\ 2. \: MC  \: and \: MZ \: are \:  tangent  \: to  \: (B)\Rightarrow MC = MZ\Leftrightarrow 5x - 9 = x + 7\Leftrightarrow x = 4 \\ 3. \: BM =  \sqrt{ {BC}^{2} + {MC}^{2}  }  =  \sqrt{ {5}^{2} +  {12}^{2}  }  = 13 \\ \Rightarrow EM = BM - BE = BM - BC = 13 - 5 = 8 \\ 4. \:  \tan(60°) = \frac{MC}{BC}  =  \frac{13 \sqrt{3}  }{ BC}\Leftrightarrow BC =  \frac{13 \sqrt{3} }{\tan(60°)} =   \frac{13 \sqrt{3} }{ \sqrt{3} }  = 13 \\ 5. \: MC =  \sqrt{ {BM}^{2}  -  {BC}^{2} }  =  \sqrt{ {20}^{2}  -  {12}^{2} }  = 16 \\ 6. \:BZ =  \sqrt{ {BM}^{2}  -  {MZ}^{2} } =  \sqrt{ {25}^{2}  -  {20}^{2} }  = 15 \\ \Rightarrow XE=BX+BE=BZ+BZ=15+15=30

7 0
3 years ago
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