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Kisachek [45]
3 years ago
6

Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the

mass in grams of water that drained out when the meniscus started just above the 25 mL mark and ended just above the stopcock? Report to the thousandth of a gram.
Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

<u>Mass of drained water = 0.025 gram</u>

Density

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Wewaii [24]

Answer: y =  -\frac{1}{2}x + 1

Step-by-step explanation:

      First, we will find the slope. The slope of perpendicular lines are negative reciprocals.

      In this case, the first slope is 2. The negative of 2 is -2, and the reciprocal of -2 is -\frac{1}{2}.

      Now, we will plug in this new slope, the point given, and solve for the <em>b</em>, or the y-intercept.

y = <em>m</em>x + <em>b</em>

(-1) =  (-\frac{1}{2})(4) + <em>b</em>

-1 =  -2 + <em>b</em>

1 = <em>b</em>

     Lastly, we will write our equation.

y = <em>m</em>x + <em>b</em>

y =  -\frac{1}{2}x + 1

          The line is y =  -\frac{1}{2}x + 1, or y = 1 - \frac{x}{2}.

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2 years ago
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HACTEHA [7]

Step-by-step explanation:

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L / W = L_1 / W_2 = 5.4 / 2.5 = 6.21 / x

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3 years ago
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Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

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2 years ago
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GrogVix [38]
1) 1/6
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3 years ago
How do I multiply 89 x 38 by using partial products? PLEASE ANSWER FAST
olga_2 [115]

Answer:

The result after partial products of 89 x 38 is 3382

Step-by-step explanation:

We need to solve 89 x 38 using partial products.

In Partial products we divide each term such that 89 can be written as 80 and 9 while 38 can be written as 30 and 8

We will multiply each term with other and then find their sum.

Multiplication is shown in figure attached.

Now adding the results of each cell in the table:

2400+640+270+72= 3382

So, the result after partial products of 89 x 38 is 3382.

Learn More:

You can learn more about partial products at:

brainly.com/question/10666510

brainly.com/question/4282963

brainly.com/question/13174282

Keywords: Partial products, product

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