2/5(x - 1) < 3/5(1 + x)
To find the solution, we can use the distributive property to simplify.
2/5x - 2/5 < 3/5 + 3/5x
Multiply all terms by 5.
2x - 2 < 3 + 3x
Subtract 2x from both sides.
-2 < 3 + x
Subtract 3 from both sides.
-5 < x
<h3><u>The value of x is greater than the value of -5.</u></h3>
Answer:
The answer to No. 4 is x = 12.
The answer to No. 5 is 160.
Step-by-step explanation:
(No. 4) The mean (average) is calculated by adding up all the numbers and then dividing by how many numbers there are.
In the first exercise, there are 6 number with a mean of 8.5. Since the mean is calculated by dividing the sum of the numbers by how many numbers there are, we know that the sum of the numbers have to be 8.5 × 6 = 51.
Subtracting all the known numbers from 51 leaves you with the only possible solution for x: 51 - 11 - 8 - 8 - 7 - 5 = 12.
(No. 5) Start by calculating the total mass of all the spiders. (16 × 175) + (24 × 150) = 6,400. Once again, to calculate the mean, divide the total sum of the numbers by how many numbers there are, in this case you divide the total mass of the spiders by how many spiders there are, leaving you with the average of 6,400 ÷ 40 = 160.
Answer:
11/15
Step-by-step explanation:
-11/3 divided by -5 also means -11/3 * -1/5
= -11/3 * -1/5
= -11*-1/3*5
=11/15
Hope this help you :3
Answer:
y is less than 3/4 x
Step-by-step explanation:
find the slope of line from the two points given. (0,0) and (4,3) which is y=3/4 x.
since the line is dashed, we know y cannot be equal to the values the line falls along, and since the shaded area is to the right, we know the values have to be less than.
Answer:
Confidence Interval = (23.776, 24.224)
Step-by-step explanation:
Restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average.
⇒ Mean = 24 ounces.
Standard Deviation = 0.8
Number of bottles used for sample = 49
⇒ n = 49
Confidence level = 95%
Corresponding z value with 95% confidence level = 1.96
Now, confidence interval is given by the following expression :
Hence, Confidence Interval = (23.776, 24.224)