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In-s [12.5K]
3 years ago
6

Need help on this question!

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0
(y2-y1)/(x2-x1)
=(0-1.5)/(-2-0)
=0.5
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An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti
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Answer:

probability that both passes a defective item is  0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is  Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

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3 years ago
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X = -3

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B.

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