Answer:
18.6 i think
Step-by-step explanation:
Answer:
Let x and y be the two numbers. Then
yx=57 and x−y=20
Cross multiplying the proportion
5x=7y or y=75x
So, x−y=20
x−75x=20⇒77x−5x=72x=20
⇒x=2140=70
y=75x=75×70=50
So smaller number is 50.
Check :yx=5070=57 and 70−50=20
Answer:
It has no slope because x 2 minus x 1 in the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction is zero, and the denominator of a fraction cannot be zero.
Step-by-step explanation:
Points:
Slope-intercept form:
slope is:
- m= (y2-y1)/(x2-x1)= (20-10)/(7-7)= 10/0,
denominator of the fraction is zero, we can't divide by zero, so this line has no slope
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It has a slope of zero because x 2 minus x 1 in the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction is zero, and the numerator of a fraction cannot be zero.
- no, numerator is not zero
It has a slope of zero because x 2 minus x 1 in the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction is zero, and the denominator of a fraction cannot be zero.
It has no slope because x 2 minus x 1 in the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction is zero, and the numerator of a fraction cannot be zero.
- no, numerator is not zero
It has no slope because x 2 minus x 1 in the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction is zero, and the denominator of a fraction cannot be zero.
150 is the perimeter of the pool
Answer:
Population of mosquitoes in the area at any time t is:

Step-by-step explanation:
assume population at any time t = P(t)
population increases at a rate proportional to the current population:
⇒dP/dt ∝ P
----(1)
where k is constant rate at which population is doubled
solving (1)

---- (2)
initial population = 400,000
population is doubled every week
⇒P(1)=2P(0)
Using (2)


In presence of predators amount is decreased by 50,000 per day
Then amount decreased per week = 350,000
In this case (1) becomes
---(3)
solving (3) by calculating integrating factor

Multiplying I.F with all terms of (3)

Integrating w.r.to t




at t=0



So, population of mosquitoes in the area at any time t is
