Hi there!
Let the width of the rectangle be called x. Then the length of the rectangle is 2x. We get the following perimeter:
![x + x + 2x + 2x = 126](https://tex.z-dn.net/?f=x%20%2B%20x%20%2B%202x%20%2B%202x%20%3D%20126)
Collect the terms
![6x = 126](https://tex.z-dn.net/?f=6x%20%3D%20126)
Divide by 6
![x = 126 \div 6 = 21](https://tex.z-dn.net/?f=x%20%3D%20126%20%5Cdiv%206%20%3D%2021)
Therefore, the width of the rectangle is 21 feet and the length is 2 × 21 = 42 feet.
Answer:
56 feet.
Step-by-step explanation:
The formula for finding the length of a rectangle, given the diagonal and the width is
. So,
. If you put this thing in the calculator you get 56.
Answer:
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
![x=\frac{y-1+\sqrt{134^2-2y+1} }{19y}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7By-1%2B%5Csqrt%7B134%5E2-2y%2B1%7D%20%7D%7B19y%7D)
![x=\frac{y-1-\sqrt{134^2-2y+1} }{19y}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7By-1-%5Csqrt%7B134%5E2-2y%2B1%7D%20%7D%7B19y%7D)
Thanks!
Mark me brainliest!
Eric started at page 26.
49-23 = 26
Answer: The answer is the number of each type of topping ordered.