Answer:
- <u>Domain</u> : -1 ≤ x ≤ 3
- <u>Range</u> : 6 ≤ y ≤ 27
Step-by-step explanation:
The domain is the set of possible x-values.
The range is the set of possible y-values.
<u>Domain</u> : -1 ≤ x ≤ 3
<u>Range</u> : 6 ≤ y ≤ 27
nuuuu the picture is blocked im on my school computer sorry :(
Answer:
8.8
Step-by-step explanation:
A=lw
A= (3.5)(2.5)
A= 8.75 ≅ 8.8
<em>plz mark me brainliest. </em>:)
Answer:
x ∈ (-∞ , -2) ∪ (1, 3)
Step-by-step explanation:
The expression is already factored. Note that for the polynomial that appears in the numerator
there are 2 roots:
![x = 3\\x = -2](https://tex.z-dn.net/?f=x%20%3D%203%5C%5Cx%20%3D%20-2)
For the polynomial that appears in the denominator there is 1 root:
![x = 1](https://tex.z-dn.net/?f=x%20%3D%201)
Note that
does not belong to the domain of f(x) because it zeroes the denominator of the function and the division between zero is not defined.
With these three roots we do the study of signs to find out when
Observe the attached image
Note that:
when
when ![x](https://tex.z-dn.net/?f=x%20%3C-2)
when ![x](https://tex.z-dn.net/?f=x%20%3C1)
Finally, we have the solution:
x ∈ (-∞ , -2) ∪ (1, 3)
x = 43, AB = 49, BC = 49 and AC =98.
Solution:
Given data:
AC = 3x - 31 and AB = x + 6
B is the midpoint of AC.
Therefore AB = BC
.
BC = x + 6
AB + BC = AC
x + 6 + x + 6 = 3x - 31
2x + 12 = 3x - 31
Add 31 on both sides, we get
2x + 43 = 3x
Subtract 2x from both sides, we get
43 = x
AB = x + 6
= 43 + 6
AB = 49
BC = 49
AC = 3x - 31
= 3(43) - 31
= 129 - 31
AC = 98
Therefore x = 43, AB = 49, BC = 49 and AC =98.