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meriva
4 years ago
13

Describe the differences between a parabola that has a horizontal directrix and a parabola that has a vertical directrix.

Mathematics
1 answer:
Readme [11.4K]4 years ago
4 0
 <span>A parabola that has a horizontal directrix is a parabola that opens up or down. 

Here are some of its components: 
1) Standard equation of a parabola with a horizontal directrix: (x-h)^2 = 4a(y-k), 
a = distance from vertex to focus 
2) Vertex at (h,k) 
3) Focus(h,k+a) 
4) Directrix: y = k-a 
5) Axis of symmetry: x = h 

A parabola that has a vertical directrix opens to the right or left and is on its side. 

Here are some components 
1) Standard equation of a parabola with a vertical directrix: (y-k)^2 = 4a(x-h) 
2) vertex (h,k) 
3) focus (h+a,k) 
4) directrix: x = h-a 
5) Axis of symmetry: y = k

Hopes this helps :)</span>
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Assume a solution of the form \Psi(x,y)=C. Taking the differential of both sides would give the ODE

\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0

where \Psi_x=2y-8x^2 and \Psi_y=x. The ODE is exact if \Psi_{xy}=\Psi_{yx}. We have

\Psi_{xy}=(2y-8x^2)_y=2

\Psi_{yx}=(x)_x=1

so the ODE is not exact. However, multiplying both sides by x gives

(2xy-8x^3)\,\mathrm dx+x^2\,\mathrm dy=0

and now

(x\Psi_x)_y=(2xy-8x^3)_y=2x

(x\Psi_y)_x=(x^2)_x=2x

so the ODE is now exact.

Now,

\Psi_x=2xy-8x^3\implies \Psi(x,y)=x^2y-2x^4+f(y)

\Psi_y=x^2=x^2+f_y\implies f_y=0\implies f(y)=C

So the ODE has solution

\Psi(x,y)=x^2y-2x^4+C=C

or simply

\boxed{x^2y-2x^4=C}

3 0
4 years ago
Please help me I need this asap
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Answer:

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Step-by-step explanation:

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