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grandymaker [24]
4 years ago
15

4 times a number increased by 2 is the same as 10 more than 2 times the number. Find the number.

Mathematics
2 answers:
densk [106]4 years ago
8 0

Answer:

4x + 2 = 10+2x

-2x             - 2x

2x + 2 = 10

      -2  - 2

2x = 8

<h2><em><u>x = 4 is the answer.</u></em></h2>
marin [14]4 years ago
3 0

Answer:

the answer is 4

Step-by-step explanation:

because 4*4+2=18

and 10+2*4=18

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Whitney needed to earn $400 to buy a ticket to a concert. If she earns $15 an hour babysitting, how many hours does she need to
MrMuchimi

Answer:

Shes needs to work 26.67 hours

Step-by-step explanation:

In order to find the amount of time she needs to work, we need to divide the total by the rate that she earns money at. She needs a total of $400 and she gets 15 every hour.

400/15=26.67

Shes needs to work 26.67 hours

4 0
3 years ago
Mr. Jones is shopping for new appliances at a store.
gogolik [260]

mr. John is shopping for new Apple eyes at a store all lights are on sale for 10% off sales tax is 7% which expression could mr. Jones use to calculate the total cost any wise X fun cost of the item the original price is $100 equal 100 and see what toys will give you the correct price

3 0
3 years ago
The coordinate plane shows Line A B.<br> What is the length of the line segment?
Lemur [1.5K]

Answer:

AB = 13 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = B(- 5, 12) and (x₂, y₂ ) = A (0, 0)

d = \sqrt{(0+5)^2+(0-12)^2}

   = \sqrt{5^2+(-12)^2}

   = \sqrt{25+144}

   = \sqrt{169}

   = 13

8 0
3 years ago
Read 2 more answers
A 400-meter Olympic-size track can be modeled with a rectangle and two semicircles.
pishuonlain [190]

The answer to both the subparts using the circumference of the circle is:

  • (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
  • (B) The area of green space on the track is 0.64m².

<h3>What is a length of a rectangle?</h3>
  • The length of the rectangle is traditionally thought of as being the longer of these two dimensions, however, when the rectangle is depicted standing on the ground, the vertical side is typically referred to as the length.

What is a circumference of a circle?

  • The distance along a circle's perimeter is referred to as its circumference.
  • Circumference of the circle formula: C = 2πr.

Here,

(A) A circuit of a racetrack is equal to the sum of the two lengths of a rectangle and the circumference of the circle.

We get:

  • = 84.39 * 2 + 73π
  • = (168.78 + 73π)m

(B) Let the area of the green space of the track is x.

Then, calculate as follows:

  • 168.78 + xπ = 400
  • x = (400 - 168.78)/π
  • x = 73.64m

So, the inner circle of distance is 73.64 - 73 = 0.64m.

Therefore, the answer to both the subparts using the circumference of the circle is:

  • (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
  • (B) The area of green space on the track is 0.64m².

To learn more about the circumference from the given link

brainly.com/question/18571680

#SPJ13

7 0
1 year ago
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF
Vsevolod [243]

First of all, this problem is properly done with the Law of Cosines, which tells us

a^2 = b^2 + c^2 - 2 b c \cos A

giving us a quadratic equation for b we can solve.  But let's do it with the Law of Sines as asked.

\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}

We have c,a,A so the Law of Sines gives us sin C

\sin C = \dfrac{c \sin A}{a} = \dfrac{5.4 \sin 20^\circ}{3.3} = 0.5597

There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse:

C_a = \arcsin(.5597)  = 34.033^\circ

C_o = 180^\circ - C_a = 145.967^\circ

Both of these make a valid triangle with A=20°.   They give respective B's:

B_a = 180^\circ - A - C_a = 125.967^\circ

B_o = 180^\circ - A - C_o = 14.033^\circ

So we get two possibilities for b:

b = \dfrac{a \sin B}{\sin A}

b_a = \dfrac{3.3 \sin 125.967^\circ}{\sin 20^\circ} = 7.8

b_o = \dfrac{3.3 \sin 14.033^\circ}{\sin 20^\circ} = 2.3

Answer: 2.3 units and 7.8 units

Let's check it with the Law of Cosines:

a^2 = b^2 + c^2 - 2 b c \cos A

0 = b^2 - (2 c \cos A)b + (c^2-a^2)

There's a shortcut for the quadratic formula when the middle term is 'even.'

b = c \cos A \pm \sqrt{c^2 \cos^2 A - (c^2-a^2)}

b = c \cos A \pm \sqrt{c^2( \cos^2 A - 1) + a^2}

b = 5.4 \cos 20 \pm \sqrt{5.4^2(\cos^2 20 -1) + 3.3^2}

b = 2.33958 \textrm{ or } 7.80910 \quad\checkmark

Looks good.

6 0
3 years ago
Read 2 more answers
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