Answer:
x = 8, y = 6
Step-by-step explanation:
2x + 5y = 46______(1)
3x - 2y = 12_______(2)
(1) x 3 --> 6x + 15y = 138
(2) x 2 --> 6x -4y = 24
(1) - (2) --> 19y = 114
y = 6 sub into (2)
3x - (2 x 6) = 12
3x = 24
x = 8
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<em><u>Please mark as brainliest!!!</u></em></h2>
Answer: x=1
Step-by-step explanation:
4 (-x+4）=12
（-4x+16）=12
-4x+16-16 =12-16
-4x/-4 =-4/-4
x=1
I don't know if this is right, please let me know if it is wrong ο(=•ω＜=)ρ⌒☆
Answer:
Infinitely many solutions
Step-by-step explanation:
Left side:
When you distribute 1/2 to the equation in the parentheses, it will be 3x-3/2.
Right side:
When you distribute 1/4 to the equation in the parentheses, it will be 3x-6/4.
6/4 can be reduced to 3/2 so it'll be 3x-3/2.
This means that the reduced form will be 3x-3/2=3x-3/2
Since the 2 sides have the same equation, there will be infinitely many solutions.
You want to know when both colleges have the same enrollment. "When" is a time thing so you are going to be solving for x. The number of students is the same and that means you will be solving for y.
Since both ys are equal, you can equate the right side of each equation to each other.
0.046 x + 0.570 = - 0.036x + 2.702 There are a number of ways to go on. The easiest is to dig out your calculator. Add 0.036x to both sides.
0.046x + 0.036x + 0.570 = 2.702
0.082x + 0.570 = 2.702 Now subtract 0.570 from both sides.
0.082x = 2.702 - 0.570
0.082x = 2.132 Divide by 0.084
x = 2.132 / 0.082
x = 26 which means you add 26 onto 1990. The year this took place was 2016
x = 2016 (That's the year there was equality in enrollment). The second one is the only year that gives 2016 as an answer. So you don't have to find y. But we'll do it anyway.
Now you have to solve for y
y = 0.046x +0.57 put 26 in for x
y = 0.046 * 26 + 0.570
y = 1.196 + 0.570
y = 1.766 enrollment numbers were equal, but this is in thousands.
y = 1766 enrollment in actual numbers of students.
Second choice <<<<<===== answer.
