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Paul [167]
3 years ago
6

Need help on this one

Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

3

Step-by-step explanation:

To simplify this expression, we will simply work with the numerator, then the denominator, and then the fraction as a whole, following PEMDAS.

Numerator:  12 - 6 + 5 * (-3)^2

= 12 - 6 + 5 * (9)

= 12 - 6 + 45

= 6 + 45

= 51

Denominator:  17

So our simplified fraction is as follows:

51/17

Which can be reduced to the whole number, 3.

Cheers.

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6 - 8x = 5x - 10x + 12<br> Please help I suck at math thank you
Irina18 [472]

Answer:

I guess it's -2

Step-by-step explanation:

6-8x = 5x - 10x + 12

∴ 10x - 8x - 5x = 12 - 6

∴ 10x- 13x = 6

∴ - 3x = 6

∴ x = -6\3

∴ x = -2

3 0
2 years ago
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2 years ago
A sequence of numbers if 0, 12, 24, 36, 48...<br> Drag tiles to complete the statements.
notsponge [240]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
ILL GIVE BRAINLIEST!!!!! <br> write a subtraction number line model. -10 -8 -6 -4 -2 0 2 4 6 8 10
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