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pentagon [3]
3 years ago
6

"In one statistics course, students reported studying an average of 9.92 hours a week, with a standard deviation of 4.54. Treati

ng this class as the population, what percent of students study more than 8 hours? (Round z score to two decimal places.)"
Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

66.28% of students study more than 8 hours

Step-by-step explanation:

The percent of students study more than 8 hour can be calculated as

P(X>8)=?

P(X>8)=P((X-mean)/sd>(8-9.92)/4.54)

The calculated z-score is -0.42.

P(X>8)=P(Z>-0.42)

P(X>8)=P(0<Z<-0.42)+P(0<Z<∞)

P(X>8)=0.1628+0.5=0.6628.

Thus, 66.28% of students study more than 8 hours.

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Flour costs $0.80 per pound and sugar costs $0.50 per pound. An order of flour and sugar weighs 15 pounds and costs $9.00. Make
LenaWriter [7]

Answer: x+y=15

0.80x+0.50y=9


Step-by-step explanation:

Let x be the amount of flour and y be the amount of sugar ordered.

Since, the order of flour and sugar weighs 15 pounds.

Therefore, x+y=15

Also, Flour costs $0.80 per pound and sugar costs $0.50 per pound.

The cost of ordered flour=$0.80x

The cost of ordered sugar=$0.50y

Now, the total cost of the order= 0.80x+0.50y=9

Hence, for the given situation the system of equations is:-

x+y=15

0.80x+0.50y=9



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