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Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0):
Alternative hypothesis (H1):
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0):
Alternative hypothesis (H1):
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
The right answer is c. –2.24, 2, 2.24
This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.
1. Using a graphing calculator.
We have the following polynomial equation:
By ordering this equation we have:
So, we can say that this equation comes from a function given by:
Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of which are:
Finally, rounding noninteger roots to the nearest hundredth we have:
2. Using a system of equations.
The ordered equation is:
By arranging to factor out we have:
Then, by factoring:
Term is a common factor, thus:
