Question

TIMED QUESTION Which are the roots of the quadratic function f(b) = b2 – 75? Select TWO options.

Answer 1

The roots of the quadratic function are

a. b = 5√3

b. b = -5√3

Further explanation

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

D = b² - 4 a c

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

An axis of symmetry of quadratic equation y = ax² + bx + c is :

$\large {\boxed {x = \frac{-b}{2a} } }$

Let us now tackle the problem!

Given:

$f(b) = b^2 - 75$

The roots of the quadratic function could be calculated when f(b) = 0 :

$0 = b^2 - 75$

$b^2 = 75$

$b = \pm \sqrt{75}$

$b = \pm \sqrt{25 \times 3}$

$b = \pm \sqrt{25} \times \sqrt{3}$

$b = \pm 5 \times \sqrt{3}$

$b = \pm 5\sqrt{3}$

$b = 5\sqrt{3} \texttt{ or } b = -5\sqrt{3}$

$\texttt{ }$

Learn more

• Solving Quadratic Equations by Factoring : brainly.com/question/12182022
• Determine the Discriminant : brainly.com/question/4600943
• Formula of Quadratic Equations : brainly.com/question/3776858

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

Answer 2

Answer:

$b=5\sqrt{3}$ (b = 5 StartRoot 3 EndRoot)

and

$b=-5\sqrt{3}$ (b = Negative 5 StartRoot 3 EndRoot)

Step-by-step explanation:

we have

$f(b)=b^{2}-75$

we know that

The roots of the quadratic function are the values of x when the value of the function is equal to zero

so

For f(b)=0

$b^{2}-75=0$

Solve for b

Adds 75 both sides

$b^{2}=75$

take square root both sides

$b=(+/-)\sqrt{75}$

Simplify

$b=(+/-)5\sqrt{3}$

therefore

$b=5\sqrt{3}$ (b = 5 StartRoot 3 EndRoot)

and

$b=-5\sqrt{3}$ (b = Negative 5 StartRoot 3 EndRoot)