Help please!!!!!!!!

Mathematics

1 answer:

enyata [817]3 years ago

5 0

I couldnt read 1-3 so I started on 4
${x}^{6}$
${5}^{6} \: \: or \: \: 15625$
${c}^{14}$
${4}^{6} \: \: or \: \: 4096$
${m}^{12}$
${h}^{36}$
${a}^{72}$
${d}^{42}$
${2}^{40}$
${3}^{3} {c}^{12}$
${a}^{3} {b}^{15}$
${g}^{48} {h}^{42}$
${x}^{18} {y}^{9}$
${20}^{6} {x}^{18}$
${32}^{5} {a}^{80} {b}^{34}$

You might be interested in

The amount $180.00 is what percent greater than $135.00

horsena [70]

33.33% is the answer.

7 0

3 years ago

How to solve question 19<br> thanks

miskamm [114]

Let $X$ be the random variable for the weight of any given can, and let $\mu$ and $\sigma$ be the mean and standard deviation, respectively, for the distribution of $X$ .

You have

$\begin{cases}\mathbb P(X377)=0.025\end{cases}$

Recall that for any normal distribution, approximately 99.7% of it lies within three standard deviations of the mean, i.e. $\mathbb P(\mu-3\sigma$ . This means 0.3% must lie outside this range, $\mathbb P(X\mu+3\sigma)=0.003$ . Because the distribution is symmetric, it follows that $\mathbb P(X$ .

Also recall that for any normal distribution, about 95% of it falls within two standard deviations of the mean, so $\mathbb P(\mu-2\sigma$ , which means 5% falls outside, and by symmetry, $\mathbb P(X>\mu+2\sigma)=0.025$ .

Together this means

$\begin{cases}\mu-3\sigma=347\\\mu+2\sigma=377\end{cases}$

Solving for the mean and standard deviation gives $\mu=365$ and $\sigma=6$ .