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MissTica
3 years ago
7

Write a program to compute answers to some basic geometry formulas. The program prompts the user to input a length (in centimete

rs) specified as a floating point value. The program then echoes the input and computes areas of squares and circles and the volume of a cube. For the squares, you will assume that the input length value is the length of a side. For the circles, this same value becomes the diameter. Use the meter value input to calculate the results in square (or cubic) meters and then print the answers in square (or cubic) meters.
Computers and Technology
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

import math

l = float(input("Enter length in cm: "))

l = l / 100;

print("Entered length is " + str(l) + " meters")

area_square = l * l

print("Area of square is " + str(area_square))

area_circle =  math.pi * l/2 * l/2

print("Area of circle is " + str(area_circle))

volume_cube =  l * l * l

print("Volume of cube is " + str(volume_cube))

Explanation:

*The code is in Python

Ask the user to enter the length in cm

Convert the length to meters and print it

Calculate the area of the square and print it (Since length is equal to a side, the area is length * length)

Calculate the area of the circle and print it (Since length is equal to the diameter, you need to divide it by two to get the radius. The area is pi * length/2 * length/2)

Calculate the volume of the cube and print it (Since length is equal to a side, the volume is length * length * length)

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2 years ago
Consider a sequence of method invocations as follows: main calls m1, m1 calls m2, m2 calls m3 and then m2 calls m4, m3 calls m5.
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Answer:

M2 is the answer for the above question.

Explanation:

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4 0
3 years ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
4 years ago
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