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Juliette [100K]
3 years ago
10

Brainliest will be awarded please answer the below question fast u will get points too.

Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

Step-by-step explanation:

For a number to be divisible by 4 you just need to worry about the 10s and 1s place.  You also want to know that the 1s cylce every 20, or in other words:

4 8 12 16 20

24 28 32 36 40 and so on.  So the only numbers that x can be there are 1, 3, 5, 7, 9.  Does that make sense?  and can you manage  the rest?

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Convert 6 4/5 to an improper fraction.
Marina86 [1]
6 4/5 as improper fraction is 34/5

5 3/4 as improper fraction is 23/4

3 1/3 by 25/4 is 8/15

14/3 by 3 1/2 is 4/3

3 1/4 by 5 1/2 is 13/22
7 0
2 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Angel and Jayden were at track practice. The track is 2/5 kilometers around.  Angel ran 1 lap in 2 minutes.  Jayden ran 3 laps
choli [55]

Answer:

6/25 km in 1 min; or 0.24 km/min

Step-by-step explanation:

The info about Angel is not necessary.

Jayden runs 3 laps in 5 mins

Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.

Distance = rate x time

6/5 km = rate (5 min)

We want to isolate r (rate), so divide both sides by 5 min

6/5 km ÷ 5 min = r

6/5 km (1/5 min) = r

6/25 km/min = r  (notice how the units worked out correctly to km/min)

So, Jayden runs 6/25 km in 1 min.

7 0
2 years ago
Read 2 more answers
Find the value of x.
son4ous [18]

Answer:

18.0

Step-by-step explanation:

==>Given:

Triangle with sides, 16, 30, and x, and a measure of an angle corresponding to x = 30°

==>Required:

Value of x to the nearest tenth

==>Solution:

Using the Cosine rule: c² = a² + b² - 2abcos(C)

Let c = x,

a = 16

b = 30

C = 30°

Thus,

c² = 16² + 30² - 2*16*30*cos 30°

c² = 256 + 900 - 960 * 0.8660

c² = 1,156 - 831.36

c² = 324.64

c = √324.64

c = 18.017769

x ≈ 18.0 (rounded to nearest tenth)

8 0
3 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
Archy [21]

Answer:

1. 12

2. the prism with a length of 7  1/2 will have a shorter width, with a width of 6

8 0
2 years ago
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