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Ganezh [65]
3 years ago
11

How to get these variables?

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Given:

Right triangle with one angle 45°

To find:

The value of q and r.

Solution:

Opposite to θ = 16

Adjacent to θ = r

Hypotenuse = q

Using trigonometric ratio formula:

$\tan \theta =\frac{\text{Opposite side to } \theta}{\text{Adjacent to } \theta}

$\tan 45^\circ =\frac{16}{r}

The value of tan 45° = 1

$1 =\frac{16}{r}

Do cross multiplication, we get

r = 16

Using trigonometric ratio formula:

$\sin \theta =\frac{\text{Opposite side to } \theta}{\text{Hypotenuse}}

$\sin 45^\circ =\frac{16}{q}

The value of sin 45° = \frac{1}{\sqrt{2} }.

$\frac{1}{\sqrt{2} }  =\frac{16}{q}

Do cross multiplication, we get

q=16\sqrt{2}

The value of r is 16 and the value of q is 16 \sqrt{2}.

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Five friends buy tickets to a carnival. They each also spend $4 on a funnel cake. They spent a total of $60. How much does one t
Butoxors [25]

Answer:

$8 for each tickets

Step-by-step explanation: 60/5 equals 12

Each friends have $12

12-4=8

Each ticked cost 8 dollars.

4 0
2 years ago
Which of the following is a correct equation for the line passing through the point (-3,2)and having slope m=2/3
natta225 [31]

Correct answers are

B = y-2=2/3(x+3)

D = 2x-3y=-12

A = y=2/3x+4

5 0
2 years ago
Select the statement that correctly describes the expression below
Kitty [74]

Answer:

B

Step-by-step explanation:

The equation is (2x+5)^2.

It can't be A because 2 is the multiplier for only x.

It can't be C because the square is outside of the equation.

It can't be D because again, the square is outside of the equation.

So the only thing left is B.

Hope this helped!


7 0
3 years ago
The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
Can anyone help me on this one?
sertanlavr [38]

Answer:

6

Step-by-step explanation:

a=1/2 b*h

a=1/2 3*4

a=1/2 12

a=6

:)

7 0
3 years ago
Read 2 more answers
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