Answer:
13.8+13.8=27.6 27.6-1=26.6 190/26.6=7.1
Height=26.6
Width=7.1
Step-by-step explanation:
Brainlist plz
The answer for the question would be D
We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0
use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6) => 6x + 8y -2z = -12
+ ( 5x + 8y +2z = 2)
------------------------
11x + 16y = -10 -> this the fourth equation
use the first and third equation:
3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
2x + 5y = -6 -> this is the fifth equaiton
use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10) => 22x + 32y = -20 -> this is the sixth equation
-11 (2x + 5y = -6) => -22x -55y = 46 -> this is the seventh equation
add 6th and 7th equation such as:
22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
- 23y = 46
<span> y = -2
solving for x, we have:
</span>2x + 5y = -6
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2
solving for y value, we have:
-x + y + z =0
z = x -y
z = 2- (-2)
z =4
The answers are the following:
x = 2
y = -2
z = 4
A. 2(x+14) = 42
(2x = 14
x = 7
2(7) + 2(14) = 14 + 28 = 42)
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
