For this case, the first thing we must do is define variables:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:
their difference is 1.6:
Solving the system we have:
We add both equations:
Then, we look for the value of y using any of the equations:
Answer:
The numbers are:
Answer:
x = 1 and y = 2
Step-by-step explanation:
Let apples are represented by x
and let oranges are represented by y
You purchase 5 pounds of apples and 2 pounds of oranges for $9. This line in equation format can be written as:
5x + 2y = 9
Your friend purchases 5 pounds of apples and 6 pounds of oranges for $17.
This line in equation format can be written as:
5x + 6y = 17
Now we have two equations:
5x + 2y = 9 -> eq (i)
5x + 6y = 17 -> eq(ii)
We can solve these equations to find the value of x and y.
Subtracting eq(i) from eq(ii)
5x + 6y = 17
5x + 2y = 9
- - -
_________
0+4y= 8
=> 4y = 8
y= 8/4
y = 2
Now, putting value of y in eq (i)
5x + 2y = 9
5x +2(2) = 9
5x +4 = 9
5x = 9-4
5x = 5
x = 1
so, x = 1 and y = 2
Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k
a) Probability that four parts are defective = 0.01374
P(4 defective) = (25 4) (0.04)^4 * (0.96)^21
P(4 defective) = 0.01374
b) Probability that at least one part is defective = 0.6396
Find the probability that 0 parts are defective and subtract that probability from 1.
P(0 defective) = (25 0) (0.04)^0 * (0.96)^25
P(0 defective) = 0.3604
1 - 0.3604 = 0.6396
c) Probability that 25 parts are defective = approximately 0
P(25 defective) = (25 25) (0.04)^25 * (0.96)^0
P(25 defective) = approximately 0
d) Probability that at most 1 part is defective = 0.7358
Find the probability that 0 and 1 parts are defective and add them together.
P(0 defective) = 0.3604 (from above)
P(1 defective) = (25 1) (0.04)^1 * (0.96)^24
P(1 defective) = 0.3754
P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358
e) Mean = 1 | Standard Deviation = 0.9798
mean = n * p
mean = 25 * 0.04 = 1
stdev = 
stdev = 
= 0.9798
Hope this helps!! :)
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