By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. If the cardboard is 12 in. long and 10 in. wide, find the dimensions of the box that will yield the maximum volume. (Round your answers to two decimal places.)
in (smallest value)
in
in (largest value)
Answer:
1.4
Step-by-step explanation:
q(1.4)=1.4
The probability that you will have to wait and additional five minutes 1/5 percent chance , I took the test
Answer:
length = 32cm; width = 20cm
Step-by-step explanation:
The answer to the question above is provided thus.
Formula for calculating the perimeter of a rectangle = 2(l + w)
Where,
l = length
w = width
Recall that perimeter is 104 cm and length is 12cm longer than the width.
Thus,
P = 2(l + w)
Since perimeter is 2 times l + w, we divide through by 2 to get l + w. That is:
Dividing through by 2
since length is length is 12cm longer than the width, we think of two numbers whose sum equals 52 and difference equals 12. The numbers are 32 and 20. That is, 32 + 20 = 52; 32 - 20 = 12.
Therefore,
104cm = 2( 32cm + 20cm)
Hence, length is 32cm while width is 20cm. The length is 12cm longer than the width such that 32cm - 20cm = 12cm.
Thus, the dimension of the rectangle whose perimeter is 104cm is 32cm + 20 cm or 32cm and 20cm.
Check,
Perimeter of a rectangle = 2( l + w)
104cm = 2( 32cm + 20cm)
104cm = 2(52cm)
104cm = 2 × 52cm
104cm = 104cm
Length is 12cm longer than the width
32cm - 20cm = 12cm