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mart [117]
3 years ago
8

Please help me I really need help it is only 1 question please answer and explain

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

3183.34 cm³

Step-by-step explanation:

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(11y + 19) ° <br> 8x °<br> 96 °
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Answer:

lol 96

Step-by-step explanation:

8 0
3 years ago
Which correctly explains how to estimate 33 percent of 87
dedylja [7]

Answer:

Round 33 percent to 30 percent and 87 to 90. Think of 30 percent as 10 percent + 10 percent + 10 percent. Find 10 percent of 90 as 9. So, 30 percent of 90 is 9 + 9 + 9, which is 27.

Step-by-step explanation:

Hope you pass! <3

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3 years ago
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Can someone please help me ....An average American throws away 4 to 5 pounds of waste each day. Make an estimate of the number o
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A typical month is 30 days so each house hold is 8 to 15 pounds a day. And the total is 240 to 450 per month
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3 years ago
A right triangle has legs with lengths equal to 10 inches and 9x inches. Its hypotenuse measures (x + 10) inches. What is the ap
katrin [286]
The approximate value of the hypotenuse is 10.25 seconds
4 0
3 years ago
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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
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