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3 years ago

Find the 8th term in the following geometric sequence. Round your answer to the nearest hundredth. 27/375, 9/75,3/15,1/3,....

Mathematics

1 answer:

Nesterboy [21]3 years ago

7 0

Answer:

2.57

Step-by-step explanation:

The common ratio of this sequence is ...

(1/3)/(3/15) = (1/3)/(1/5) = 5/3

Each additional term is 5/3 times the previous one, so the 8th term will be (5/3)^4 times the 4th term (the last one given). It is ...

(1/3)·(5/3)^4 = 625/243 ≈ 2.57

_____

The generic n-th term (an) is ...

an = a1·r^(n-1)

where a1 is the first term and r is the common ratio. We can make use of this formula to find the 8th term:

a8 = (27/375)·(5/3)^7 = (3^3/3^7)·(5^7/(3·5^3)) = 5^4/3^5 = 625/243 ≈ 2.57

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Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

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We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

2π

or x=

6n±2

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

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3 years ago