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fenix001 [56]
3 years ago
5

find the equation of the line passing throught the point (-4,2) that is perpendicular to the line 5x+3y=7.

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0
Point Slope: Y +2 = (3/5)(x-4)
Answer: y = 3/5x - (-14/5)
Katena32 [7]3 years ago
4 0

5x + 3y = 7 => y = 5/3x + 7/3

take the reciprocal of 5/3

2 = 3/5(-4) + b

2 = -12/5 +b

22/5 = b

the equation is y = 3/5x + 22/5

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Please help!! 55 points!!
Sedbober [7]
28/80 and then you simplify it by dividing the numerator and denominator by 4 and you get 7/20.

B. 7/20 is the correct answer
5 0
3 years ago
J^2 over 2j times 2j over 3g
Serhud [2]

Answer:

D

Step-by-step explanation:

given \frac{j^2}{2j} × \frac{2j}{3g}

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= \frac{j^2}{3g} → D


5 0
3 years ago
Wha are the equations. of the asymptotes of the graph of the function f(x)=3x^2-2x-1/x^2+3x+10
Leviafan [203]
The asymptote is the line the graph comes close to but never touches, so if you graph it out you should be able to see it! Sorry I couldn't help any more but good luck

3 0
3 years ago
Need a lil help please
Georgia [21]

Answer:

  • B(2, 4)

Step-by-step explanation:

<u>Given points:</u>

  • A(-1, -9) and M(0.5, -2.5)

Let the coordinates of B are (x, y)

<u>Use midpoint formula to determine the point B:</u>

  • 0.5 = (- 1 + x)/2 ⇒ 1 = -1 + x ⇒ x = 1 + 1 = 2
  • -2.5 = (-9 + y)/2 ⇒ -5 = -9 + y ⇒ y = -5 + 9 = 4

3 0
3 years ago
Please help me with this
Masja [62]

Answer:

c = a - 16

Step-by-step explanation:

Given

a = b + 12 ( subtract 12 from both sides )

a - 12 = b

Substitute b = a - 12 into b = c + 4

a - 12 = c + 4 ( add 12 to both sides )

a = c + 16  ( subtract 16 from both sides )

c = a - 16

5 0
2 years ago
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