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guajiro [1.7K]
3 years ago
6

16 m 10 12 m 3 m 3m 14 m Find the

Mathematics
1 answer:
Stels [109]3 years ago
7 0

Answer:

u,9fuxtd5ddugy5fud4d

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Which graph represents the function f(x)=x4+4x3−12x2−32x+64?
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f(x)=x^4+4x^3-12x^2-32x+64

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So  as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first  graph

x intercepts of first graph is -4  and 2

Plug in -4 for x in f(x) and check whether we get 0

f(x)=x^4+4x^3-12x^2-32x+64

f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0

Now plug in 2 for x and check

f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0

So -4  and 2  are the x intercepts that satisfies f(x)

Hence first option is the graph of f(x)=x^4+4x^3-12x^2-32x+64





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