the 2nd answer makes the most since
Answer:
Shhshshsjjsjsjnsns
Step-by-step explanation:
Kaksmsndnndndnd
Answer:
7
Step-by-step explanation:
~Shoto Todoroki here~
Let's consider what we are asked. The domain is defined as a set of points that satisfy the equation on the x-ordinate.
So, essentially, we need to find if and what the restriction on x is.
Let's now consider just f(x) because g(x) is completely irrelevant to the question.
f(x) = 2 - x^(1/2)
Since f(x) can never be 0 for a defined function, let's consider when f(x) = 0 to find a restriction on x.
2 - x^(1/2) = 0
2 = x^(1/2)
+-4 = x
But we can only take the positive 4 because inside a square root has to always be positive (unless you're dealing with complex numbers), so the only restriction is that x cannot be equal to 4.
<h2>Therefore, our domain is:<u><em> x >= 0; x =/= 4</em></u></h2>
hope this helps :D
Answer:
13
Step-by-step explanation:
Replace X with 2
Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)
g(x) = 3(2)^2 – 2(2) + 5
Next conduct PEMDAS
Exponents are first so solve 2^2 which is 2 x 2 = 4
g(x) = 3(4) – 2(2) + 5
Next step is multiplication multiply 3 x 4 and 2x2
g(x) = 12 – 4 + 5
conduct adding and subtracting left from right
g(x) = 13
