Answer:
The enzyme you will be studying in this experiment is lactase, and the reaction it catalyzes is the hydrolysis of the disaccharide lactose into the monosaccharides galactose and glucose.
Explanation:
Answer:
This question lacks options, options are:
A) ATP
B) NADP
C) Pryuvate
D) glucose
E) acetyl-CoA.
The correct answer is C) Pyruvate.
Explanation:
Pyruvate is a very important compound for the cell since it is a key substrate for energy production and glucose synthesis (neo-glycogenesis), that is, pyruvate is the end product of glucose breakdown in glycolysis. Before entering the mitochondria, it can be converted to lactate, through an anaerobic reaction (in the absence or under oxygen supply) of low performance in energy production, when the main pathway is interfered with. It can also be converted to the amino acid alanine. Within the mitochondria, it can be transformed, by pyruvate dehydrogenase (PDH), into acetyl-coenzyme A (acetyl-CoA), the entry point (substrate) of the Krebs cycle. In addition, by means of pyruvate carboxylase, it can be transformed into oxalacetate, which constitutes the first step in neoglycogenesis.
Answer:
Species interaction- competition, predation, parasitism, mutualism, and commensalism.
Cells need to reproduce for growth, repair, or replacements. Cells divide whenever a tissue / organ / organism is growing or needs repair.
Hope this helps :)
Corpus callosum <span>is the thick band of neurons that connects cerebral hemispheres</span>
