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Kruka [31]
3 years ago
6

In the interval 0 degrees < x < 360 degrees, find the values of x for which cos x = 0.7252. Give your answers to the neare

st degree.
Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0

Answer:

115° and 245°

Step-by-step explanation:

Given

cos x = - 0.4226

Since cos x < 0 then x is an angle in the second / third quadrants, thus

x =  (0.4226) = 65° ← related acute angle , thus

x = 180° - 65° = 115° ← angle in second quadrant

x = 180° + 65° = 245° ← angle in third quadrant

Vikentia [17]3 years ago
5 0

Answer:

x=\{44\º, 317\º\}

Step-by-step explanation:

The interval given is (0, 360\º) \text{ or } (0, 2\pi)

In exercises of this kind I usually use

\cos \left(x\right)=a\quad \Rightarrow \quad \:x=\arccos \left(a\right)+360\º n, n \in \mathbb{Z}

\quad \:x=\arccos \left( 0.7252\right)+360\º n, n \in \mathbb{Z}

And \arccos \left( 0.7252\right) \approx 43.5^{\circ \:}

But once we have the solution for cos in two different quadrants, I mean, Quadrant I and Quadrant IV angle.

To the nearest degree, we have

x=\{44\º, 317\º\}

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Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

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Harrizon [31]
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3 years ago
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Which expression is equivalent to m^2-13m-30?
sergiy2304 [10]

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Step-by-step explanation:

You have the quadratic equation given in the problem:

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Therfore, you obtain the following equivalent expression:

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If you don't want to apply the method above, you can use the quadratic formula:

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