In the interval 0 degrees < x < 360 degrees, find the values of x for which cos x = 0.7252. Give your answers to the neare
st degree.
2 answers:
Answer:
115° and 245°
Step-by-step explanation:
Given
cos x = - 0.4226
Since cos x < 0 then x is an angle in the second / third quadrants, thus
x = (0.4226) = 65° ← related acute angle , thus
x = 180° - 65° = 115° ← angle in second quadrant
x = 180° + 65° = 245° ← angle in third quadrant
Answer:

Step-by-step explanation:
The interval given is 
In exercises of this kind I usually use


And 
But once we have the solution for cos in two different quadrants, I mean, Quadrant I and Quadrant IV angle.
To the nearest degree, we have

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