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3 years ago

Reduce the fraction 36/48 to its lowest

Mathematics

2 answers:

KonstantinChe [14]3 years ago

4 0

Answer:

3/4

Step-by-step explanation:

36/48

Divide the top and bottom by 12

36/12 = 3

48/12 =4

36/48 = 3/4

tekilochka [14]3 years ago

3 0

Answer:

3/4

Step-by-step explanation:

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HURRY 25 POINTS IF RIGHT

Elina [12.6K]

Answer:

A) 160 minutes

Step-by-step explanation:

First we write an equation

0.05x + 24 = 32

Subtract 24 from both sides

0.05x=8

Divide by 0.05 on both sides

x=160

So that mean at 160 minutes the plans will cost the same!

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3 years ago

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Write the polynomial in standard form and classify it by degree and by number of terms 2x-4x^3-7

Vinvika [58]

4x^3+2x-7

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2 years ago

Daniel's goal is to walk 100 miles.• He walks 5 miles every day.• He has

lozanna [386]

Answer:

65 miles

Step-by-step explanation:

Given:

k = how many more miles Daniel has to walk
Goal = 100 miles
Daily miles = 5 miles
Number of days already walked = 7 days

Equation:

5 × 7 + k = 100

Solving:

⇒ 5 × 7 + k = 100

⇒ 35 + k = 100

⇒ k = 100 - 35

⇒ k = 65

3 0

2 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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2 years ago

What is the greatest common factor of the expression 12x4+18x2

Nata [24]

Answer:

Step-by-step explanation:

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3 years ago

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