Question

7 - 3[(n 3 + 8n) ÷ (-n) + 9n 2]

Answer 1

Answer:

$-24n^{2} +31$

Step-by-step explanation:

Given: $7-3[(n^{3} +8n)\div (-n)+9n^{2} ]$

Now simplifying expression using PEDMAS

First solving for small parenthesis.

taking common of n

= $7-3[n(n^{2} +8)\div (-n)+9n^{2} ]$

using law of indices, $\frac{x^{m} }{x^{n} } = x^{m-n}$

= $7-3[-(n^{2} +8)+9n^{2} ]$

Opening parenthesis

= $7-3[-n^{2} -8+9n^{2} ]$

= $7-3[ -8+8n^{2} ]$

Again using distributive property of multiplication

= $7+24-24n^{2}$

= $-24n^{2} +31$

Hence, the answer is $-24n^{2} +31$