Answer: 10:55
Step-by-step explanation:
Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.
The time the buses will be back at the depot simultaneously will be when:
N(a) * 25mins = N(b) * 35mins
Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.
Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc
Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc
This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.
So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is
at 08:00 + 2:55 = 10:55
the answer should be the third option
The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:
To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
Answer:
Solution given:
we have
setup price =$30
as rate for 1 print tickets =$1.05/tickets
so
for t
t=$30+$1.05*t
is a required expression.
the
cost of 300 tickets:
300 tickets =$30+$1.05*300=$345
$345is the cost of 300 tickets.
Answer:
11/6
Step-by-step explanation:
<u>Step 1: Convert to Improper fractions</u>
3 1/3 = 3*3/3 + 1/3 = 9/3 + 1/3 = 10/3
1 1/2 = 1*2/2 + 1/2 = 2/2 + 1/2 = 3/2
<u>Step 2: Make common denominators</u>
10/3 * 2/2 = 20/6
3/2 * 3/3 = 9/6
<u>Step 3: Subtract</u>
20/6 - 9/6
11/6
Answer: 11/6
