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3 years ago

Solve, using linear combination. 4x + y = 5 3x + y = 3

Mathematics

1 answer:

Daniel [21]3 years ago

5 0

The answer is (2,-3)

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X2 – 12x + 37 = 0 in simplest a + bi form

Andreas93 [3]

Answer:

x=6+1

Step-by-step explanation:

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3 years ago

What will happen to the mean of the data below if the outlier, 57, is added? 23,28, 27, 25,25,22,25 A.The mean will not change B

Anvisha [2.4K]

Answer is c (there is not a enough info given)

3 0

3 years ago

Y = 7/8u + 9, solve for u

vivado [14]

Answer:

$u=\frac{8y-72}{7}$

Step-by-step explanation:

Flip the equation.

$\frac{7}{8}u+9=y$

Add -9 to both sides

$\frac{7}{8}u+9(-9)=y(-9)$

$\frac{7}{8}u=y-9$

Divide both sides by 7/8

$u=\frac{8y-72}{7}$

hope this helps

3 0

3 years ago

. Which algebraic expression is equivalent to the expression below?

I am Lyosha [343]

Since you are not distributing at all, you can ignore the parenthesis :)

When ignoring the parenthesis your equation is
18x + 11 - 4x

Then just combine like terms :)

14x + 11

Your answer is C.

Hope this helped!

5 0

3 years ago

Simplify

OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$

3 0

3 years ago