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CaHeK987 [17]
3 years ago
11

Jamie made buns and then sold them for $3 each. If Jamie spent $45 to make all the buns, how many buns need to be sold so that J

amie doesn't lose money?
Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

15

Step-by-step explanation:

45/3 = 15

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At Marco's school, 5/8 of the students are in the band. What percent of the students are in the band?
Harman [31]
62.5%

5/8 = 0.625 then multiply by 100% to get in terms of percent of 62.5%
7 0
3 years ago
If 112 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $and total receipts for the con
Brut [27]

Answer:

42 child and 70 adult

Step-by-step explanation:

Let a = number of adult tickets

c = number of child tickets

a+c = 112

2.25a + 1.75c = 231

Solve the first equation for a

a = 112-c

Substitute this into the second equation

2.25(112-c) + 1.75c = 231

Distribute

252 - 2.25c +1.75c = 231

Combine like terms

252 -.5c = 231

Subtract 252 from each side

252-252 -.5c = 231-252

-.5c = -21

Divide each side by -.5

-.5c/-.5 = -21/ -.5

c = 42

Now can find a

a = 112-c

a = 112-42

a = 70

4 0
3 years ago
Read 2 more answers
The soccer players are in motion as they run up and down the field in the tournament at the end of the video to score a goal. On
mylen [45]

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6 0
3 years ago
Please help!!<br><br> show work(factoring) <br><br> u^4 - 3u^2 - 4
Schach [20]
Answer: (u^2+1) * (u-2) * (u+2)
5 0
3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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