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emmainna [20.7K]
4 years ago
13

Help plZ and thanks​

Mathematics
1 answer:
sleet_krkn [62]4 years ago
7 0

Answer:

it would be the one over six

Step-by-step explanation:

there are three possibilities out of eighteen so it would simplify to one over six  

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You need to first start your body paragraph with your main idea or argument, then write all the evidence that you have for that main idea/argument then elaborate. Finally you need to close off the paragraph nicely so that is flows well into your next body paragraph
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On a coordinate plane, polygon GHIJ translates 8 units to the left to form polygon G'H'I'J'. Which of the following equations is
lana66690 [7]
A. True. This is because distances are preserved and kept the same. 

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C. True. Corresponding angles are congruent. 

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7 0
3 years ago
I need help pls and thank u
spayn [35]

Find the difference between the midpoint and the known endpoint by subtracting the X and Y values from each other:


X: 10 - 6 = 4

Y: 7 - 4 = 3


Now add those values to the midpoint to find the other endpoint:


X: 10 +4 = 14

Y: 7 +3 = 10


Endpoint = (14,10)

4 0
3 years ago
HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). \frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}

2). \frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}

=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

3). \frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}

=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

=\frac{3x(x-5)}{x^{2}-7x+10}

=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}

4). \frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}

=\frac{-x}{4x-5}-\frac{2x}{8x-11}

=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}

=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}

=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}

5). \frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}

=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP THANK YOU!!
Stells [14]

Answer:

Second graph

Step-by-step explanation:

See attached image.

3 0
2 years ago
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