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3 years ago

What is $112 marked down 40%

Mathematics

1 answer:

Vilka [71]3 years ago

5 0

The final price would be $67.20

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I will be marking brainliest please help me with these questions.

krek1111 [17]

Answer/Step-by-step explanation:

1. To find the area of the shaded region, you'd find the area of the white rectangular shape, next, find the area of the whole triangular shape, then find the difference of their areas to get the area of the shaded region. Thus, the formula to use would be:

Area of shaded region = area of triangle - area of rectangle

Area of shaded region = ½*base*height - length*width

1. a. Volume of triangular prism = area of triangular base * height of prism

Volume of triangular prism = ½bh * H

Where,

b = 6 m

h = 4 m

H = 8 m

Substitute

Volume of prism = ½*6*4*8

Volume of prism = 96 m³

b. Volume of sphere = ⁴/3πr³

Where,

r = 9 cm

Substitute

Volume = ⁴/3*π*9³

Volume = ⁴/3*π*729

Volume ≈ 3,053.6 cm³ (nearest tenth)

2. Use Pythagorean theorem to find the height of the cone

radius of the cone (r) = ½(16) = 8 cm

Slant height (l) = 11 cm

height (h) = ?

Using Pythagorean theorem, we have:

h = √(l² - r²)

Substitute

h = √(11² - 8²)

h = √(57)

h ≈ 7.5 cm (nearest tenth)

b. Volume of the cone = ⅓πr²h

where,

r = 8 cm

h = 7.5 cm

Volume = ⅓*π*8²*7.5

Volume = 502.7 cm³ (nearest tenth)

7 0

3 years ago

Which expression results from using the Distributive Property? 2(5 + 3r)

Natasha_Volkova [10]

Answer:

6r + 10

Explanation:

2(5 + 3r)

= (2)(5 + 3r)

= (2)(5) + (2)(3r)

= 10 + 6r

= 6r + 10

5 0

3 years ago

If you have 2 shirts 2 jackets and 2 skirts how many outfits can you make

zvonat [6]

Hello!

If you assume that with each outfit you must use at least one of each shirt, jacket, and skirt, you have a 1/2 chance of selecting one of each. Since it is a compound event (an outfit), you will multiply each singular probability (shirt, jacket, skirt) together.

$\frac{1}{2}$ · $\frac{1}{2}$ · $\frac{1}{2}$ = $\frac{1}{8}$

You can make eight different outfits.

I hope this helps!

8 0

3 years ago

Need help asap please!

RUDIKE [14]

Answer:

$\textsf{$f(1) = \boxed{1}$ , meaning when a $\boxed{1}$ is rolled on the die, the player is awarded}\\\\ \textsf{ $\boxed{1}$ point. This interpretation $\boxed{\sf makes \; sense}$ in the context of the problem.}$

$\textsf{$f(4.5) = \boxed{8}$ , meaning when a $\boxed{4.5}$ is rolled on the die, the player is awarded} \\\\ \textsf{ $\boxed{8}$ points. This interpretation $\boxed{\sf does \; not \; make \; sense}$ in the context of the problem.}$

$\textsf{$f(10) = \boxed{19}$ , meaning when a $\boxed{10}$ is rolled on the die, the player is awarded} \\\\ \textsf{ $\boxed{19}$ points. This interpretation $\boxed{\sf does \; not \; make \; sense}$ in the context of the problem.}$

$\textsf{Based on the observations above, it is clear that an appropriate domain for the}\\\\ \textsf{function is $\boxed{ \{1, 2, 3, 4, 5, 6\}}$ .}$

Step-by-step explanation:

<u>Given function</u>:

$f(x)=2x-1$

where:

x is the value rolled on the six-sided die.
The sides of the die are labelled 1 to 6.

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f(1) means the value of the function when x = 1.

Therefore, substitute x = 1 into the given function to find f(1):

$\begin{aligned}x=1 \implies f(1)&=2(1)-1\\&=2-1\\&=1\end{aligned}$

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f(4.5) means the value of the function when x = 4.5.

Therefore, substitute x = 4.5 into the given function to find f(4.5):

$\begin{aligned}x=4.5 \implies f(4.5)&=2(4.5)-1\\&=9-1\\&=8\end{aligned}$

As the faces of the six-sided die are labelled 1 to 6, the only values of x that make sense are 1, 2, 3, 4, 5 and 6. Therefore, rolling a "4.5" does not make sense.

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f(10) means the value of the function when x = 10.

Therefore, substitute x = 10 into the given function to find f(10):

$\begin{aligned}x=10 \implies f(1)&=2(10)-1\\&=20-1\\&=19\end{aligned}$

As the faces of the six-sided die are labelled 1 to 6, the only values of x that make sense are 1, 2, 3, 4, 5 and 6. Therefore, rolling a "10" does not make sense.

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The domain of a function is the set of all possible x-values.

As the faces of the six-sided die are labelled 1 to 6, the only possible values of x are 1, 2, 3, 4, 5 and 6.

$\textsf{Based on the observations above, it is clear that an appropriate domain for the}\\\\ \textsf{function is $\boxed{ \{1, 2, 3, 4, 5, 6\}}$ .}$

The domain can also be written as:

$\{x \in \mathbb{N} \; | \; 1 \leq x \leq 6 \}$