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Masja [62]
3 years ago
12

The exponential function f(x) has a horizontal asymptote at y=3 what is the end behaviour of f(x)?

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:  C) as x → -∞, y → 3

                    as x→ ∞ , y → ∞

<u>Step-by-step explanation:</u>

see graph

Notice that as x approaches negative infinity (goes to the left), the y value approaches the asymptote of y = 3.

And as x approaches positive infinity (goes to the right), the y-value increases without bound so goes to infinity.

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a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0
4 years ago
What's 00.5 in a fraction?
Vikentia [17]
1/2. it is one half because it is half of 1
6 0
3 years ago
Read 2 more answers
Your paycheck this week is $241. You put the $114 in a savings account that pays an interest
antiseptic1488 [7]

Answer:

$122.9

Step-by-step explanation:

Given data

Principal= $114

Rate= 3.9%

Time= 2 years

The amount in the account is given as

A=P(1+rt)

substitute

A=114(1+0.039*2)

A=114(1+0.078)

A=114(1.078)

A=$122.9  

5 0
3 years ago
A pattern is made from four congruent squares.
Mashutka [201]

Answer:

c is marked on the diagram

c

3 0
3 years ago
I need help with a math question please?
elena55 [62]
To find the tan x use the following formula
tan x = (sin x)/(cos x)
tan x = (1/2)/(sqrt (3)/2)
tan x = 1/sqrt (3) = sqrt (3)/3 or E
6 0
4 years ago
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