4,680 I do it like this 50 percent is 3600 then 10 percent is 720 and 5 percent is 360 add then you get 4,680
Shift left 4 units
rotate clockwise 270 degrees about the origin
not sure about the statement though
5x + 2y =9
X + y= -3
5x+2y=9
2x+2y=-6
__________
3x =15
X =5
5+y=-3
Y=-8
Answer is : (5,-8)
Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)



so
the greatest number of lunch is 

Hence
the greatest number of dinner is 
therefore
the greatest number of meals is

<u>the answer is</u>
